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29=57x-5x^2
We move all terms to the left:
29-(57x-5x^2)=0
We get rid of parentheses
5x^2-57x+29=0
a = 5; b = -57; c = +29;
Δ = b2-4ac
Δ = -572-4·5·29
Δ = 2669
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{2669}}{2*5}=\frac{57-\sqrt{2669}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{2669}}{2*5}=\frac{57+\sqrt{2669}}{10} $
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